IP-11.c¶
Problem Statement
Write a program to merge two sorted integer arrays to form a single sorted array.
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta amitdutta4255@gmail.com |
| Date | 03 Jan 2026 |
| License | MIT License (See the LICENSE file for details) |
| Difficulty | Beginner (index: 3 / 10) |
Concepts¶
Beta Feature
This concept detection system is still in beta and may occasionally show incorrect or incomplete results.
- Pointers
- Recursion
- Array
- Iteration
Actions¶
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Source Code¶
#include <stdio.h>
#include <stdlib.h>
void merge(int[], int, int[], int);
int main()
{
int a[] = {10, 30, 50, 70, 90};
int b[] = {20, 40, 60, 80, 100};
int n1 = sizeof(a) / sizeof(a[0]);
int n2 = sizeof(b) / sizeof(b[0]);
merge(a, n1, b, n2);
return 0;
}
void merge(int a[], int n1, int b[], int n2)
{
int n = n1 + n2;
int *c = (int *)malloc(n * sizeof(int));
int i, j, k;
i = j = k = 0;
while (i < n1 && j < n2)
{
if (a[i] < b[j])
{
c[k++] = a[i++];
}
else
{
c[k++] = b[j++];
}
}
while (i < n1)
{
c[k++] = a[i++];
}
while (j < n2)
{
c[k++] = b[j++];
}
printf("Merged Array:");
for (i = 0; i < n; i++)
{
printf(" %d", c[i]);
}
free(c);
}
Explanation¶
Explain with AI
Copy the prompt below and paste it into any AI assistant.
You are explaining a C programming code to a beginner.
STRICT RULES:
- Only use the given code. Do NOT assume anything not present.
- Do NOT add extra examples.
- Keep explanation clear and short.
- If something is unclear, say "Not clear from code".
- Follow the exact format below. Do NOT change headings.
FORMAT:
[START]
## What it does
(Explain the overall purpose in 1-2 sentences)
## Step-by-step
(Explain how the code works in steps, simple language)
## Key Concepts
(List concepts like loop, condition, function, etc.)
## Notes
(Mention any limitations, errors, or assumptions)
[END]
CODE (IP-11.c):
#include <stdio.h>
#include <stdlib.h>
void merge(int[], int, int[], int);
int main()
{
int a[] = {10, 30, 50, 70, 90};
int b[] = {20, 40, 60, 80, 100};
int n1 = sizeof(a) / sizeof(a[0]);
int n2 = sizeof(b) / sizeof(b[0]);
merge(a, n1, b, n2);
return 0;
}
void merge(int a[], int n1, int b[], int n2)
{
int n = n1 + n2;
int *c = (int *)malloc(n * sizeof(int));
int i, j, k;
i = j = k = 0;
while (i < n1 && j < n2)
{
if (a[i] < b[j])
{
c[k++] = a[i++];
}
else
{
c[k++] = b[j++];
}
}
while (i < n1)
{
c[k++] = a[i++];
}
while (j < n2)
{
c[k++] = b[j++];
}
printf("Merged Array:");
for (i = 0; i < n; i++)
{
printf(" %d", c[i]);
}
free(c);
}