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pc005.c

Problem Statement

Pattern : 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 for n = 5

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 2 / 10)

Concepts

Beta Feature

This concept detection system is still in beta and may occasionally show incorrect or incomplete results.

  • Recursion
  • Sorting (possible)
  • Iteration

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Source Code

#include <stdio.h>
int main()
{
    int i, j, n;
    long long temp1 = 0, temp2 = 1, temp3;
    printf("Enter n : ");
    scanf("%d", &n);
    printf("1\n");
    for (i = 2; i <= n; i++)
    {
        for (j = 1; j <= i; j++)
        {
            temp3 = temp1 + temp2;
            printf("%lld\t", temp3);
            temp1 = temp2;
            temp2 = temp3;
        }
        printf("\n");
    }
    return 0;
}

Explanation

Explain with AI

Copy the prompt below and paste it into any AI assistant.

    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (pc005.c):

    #include <stdio.h>
    int main()
    {
        int i, j, n;
        long long temp1 = 0, temp2 = 1, temp3;
        printf("Enter n : ");
        scanf("%d", &n);
        printf("1\n");
        for (i = 2; i <= n; i++)
        {
            for (j = 1; j <= i; j++)
            {
                temp3 = temp1 + temp2;
                printf("%lld\t", temp3);
                temp1 = temp2;
                temp2 = temp3;
            }
            printf("\n");
        }
        return 0;
    }