luc016.c¶
Problem Statement
Given the coordiantes (x, y) of center of a circle and its radius, write a program that will determine whether a point lies inside the circle, on the circle or outside the circle. (Hint : Use sqrt() and pow() functions.)
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta amitdutta4255@gmail.com |
| Date | 12 Dec 2025 |
| License | MIT License (See the LICENSE file for details) |
| Difficulty | Beginner (index: 1 / 10) |
Concepts¶
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- Pointers
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Source Code¶
#include <stdio.h>
#include <math.h>
// Define a small tolerance value (EPSILON) for reliable floating-point comparison
#define EPSILON 0.0001
int main()
{
double h, k;
double R;
double x, y;
double distance_sq;
printf("Enter the center coordinates (h, k) : ");
scanf("%lf %lf", &h, &k);
printf("Enter the radius (R) : ");
scanf("%lf", &R);
printf("Enter the point P coordinates (x, y) : ");
scanf("%lf %lf", &x, &y);
distance_sq = pow(x - h, 2) + pow(y - k, 2);
double radius_sq = R * R;
// Case 1: On the circle (D^2 = R^2) - Use EPSILON for safety!
if (fabs(distance_sq - radius_sq) < EPSILON)
{
printf("The point P(%g, %g) lies ON THE CIRCLE.\n", x, y);
}
// Case 2: Inside the circle (D^2 < R^2)
else if (distance_sq < radius_sq)
{
printf("The point P(%g, %g) lies INSIDE THE CIRCLE.\n", x, y);
}
// Case 3: Outside the circle (D^2 > R^2)
else
{
printf("The point P(%g, %g) lies OUTSIDE THE CIRCLE.\n", x, y);
}
return 0;
}
Explanation¶
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## What it does
(Explain the overall purpose in 1-2 sentences)
## Step-by-step
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## Key Concepts
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## Notes
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[END]
CODE (luc016.c):
#include <stdio.h>
#include <math.h>
// Define a small tolerance value (EPSILON) for reliable floating-point comparison
#define EPSILON 0.0001
int main()
{
double h, k;
double R;
double x, y;
double distance_sq;
printf("Enter the center coordinates (h, k) : ");
scanf("%lf %lf", &h, &k);
printf("Enter the radius (R) : ");
scanf("%lf", &R);
printf("Enter the point P coordinates (x, y) : ");
scanf("%lf %lf", &x, &y);
distance_sq = pow(x - h, 2) + pow(y - k, 2);
double radius_sq = R * R;
// Case 1: On the circle (D^2 = R^2) - Use EPSILON for safety!
if (fabs(distance_sq - radius_sq) < EPSILON)
{
printf("The point P(%g, %g) lies ON THE CIRCLE.\n", x, y);
}
// Case 2: Inside the circle (D^2 < R^2)
else if (distance_sq < radius_sq)
{
printf("The point P(%g, %g) lies INSIDE THE CIRCLE.\n", x, y);
}
// Case 3: Outside the circle (D^2 > R^2)
else
{
printf("The point P(%g, %g) lies OUTSIDE THE CIRCLE.\n", x, y);
}
return 0;
}