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lucproblem007.c

Problem Statement

Two numbers are entered through the keyboard. Write a program to find the value of one number raised to the power of another

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 1 / 10)

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Source Code

#include <stdio.h>
int main()
{
    double num, result;
    int power, i = 1;
    printf("Enter the numbers in 'num^power' format : ");
    // checking if the input is valid or not
    if (scanf("%lf^%d", &num, &power) != 2)
    {
        printf("\nPlease enter numbers.");
        return 1;
    }
     // result for the negetive input
    if (power < 0)
    {
        printf("\nPlease use a positive number as power.");
        return 1;
    }
    //  Hard codded result for input '0' (zero)
    if (power == 0)
    {
        printf("\n%g to the power of %d is : 1", num, power);
        return 0;
    }
    result = num;
    while (i <= power - 1)
    {
        result = result * num;
        i++;
    }
    printf("\n%g to the power of %d is : %g", num, power, result);
    return 0;
}

Explanation

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

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    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

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    [END]

    CODE (lucproblem007.c):

    #include <stdio.h>
    int main()
    {
        double num, result;
        int power, i = 1;
        printf("Enter the numbers in 'num^power' format : ");
        // checking if the input is valid or not
        if (scanf("%lf^%d", &num, &power) != 2)
        {
            printf("\nPlease enter numbers.");
            return 1;
        }
         // result for the negetive input
        if (power < 0)
        {
            printf("\nPlease use a positive number as power.");
            return 1;
        }
        //  Hard codded result for input '0' (zero)
        if (power == 0)
        {
            printf("\n%g to the power of %d is : 1", num, power);
            return 0;
        }
        result = num;
        while (i <= power - 1)
        {
            result = result * num;
            i++;
        }
        printf("\n%g to the power of %d is : %g", num, power, result);
        return 0;
    }