`P020.c`¶

Problem Statement

WAP to calculate and display the maturity amount taking the sum and number of days as input. No. of Days Rate of Interest Upto 180 days 5.5 % 181 to 364 days 7.5 % exact 365 days 9.0 % more than 365 days 8.5 %

Metadata¶

Property	Detail
Author	Amit Dutta (amitdutta4255@gmail.com)
License	MIT
Difficulty	Beginner (index: 1 / 10)

Concepts¶

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Recursion
Pointers

Actions¶

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Source Code¶

#include <stdio.h>
int main()
{
    double nod, amt, s, i;
    printf("Enter the amount and the time in days : ");
    scanf("%lf %lf", &s, &nod);
    if (nod <= 180)
        i = (s * 5.5 * (nod / 365)) / 100;
    else if (nod > 180.0 && nod <= 364.0)
        i = (s * 7.5 * (nod / 365)) / 100;
    else if (nod == 365.0)
        i = (s * 9.0 * 1) / 100;
    else if (nod > 365.0)
        i = (s * 8.5 * (nod / 365)) / 100;
    amt = s + i;
    printf("Amount to be paid : %g", amt);
    return 0;
}

Explanation¶

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (P020.c):

    #include <stdio.h>
    int main()
    {
        double nod, amt, s, i;
        printf("Enter the amount and the time in days : ");
        scanf("%lf %lf", &s, &nod);
        if (nod <= 180)
            i = (s * 5.5 * (nod / 365)) / 100;
        else if (nod > 180.0 && nod <= 364.0)
            i = (s * 7.5 * (nod / 365)) / 100;
        else if (nod == 365.0)
            i = (s * 9.0 * 1) / 100;
        else if (nod > 365.0)
            i = (s * 8.5 * (nod / 365)) / 100;
        amt = s + i;
        printf("Amount to be paid : %g", amt);
        return 0;
    }

P020.c¶