P053.c¶
Problem Statement
Print all pattern
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta amitdutta4255@gmail.com |
| Date | 12 Dec 2025 |
| License | MIT License (See the LICENSE file for details) |
| Difficulty | Beginner (index: 2 / 10) |
Concepts¶
Beta Feature
This concept detection system is still in beta and may occasionally show incorrect or incomplete results.
- Pointers
- Sorting (possible)
- Iteration
Actions¶
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Source Code¶
#include <stdio.h>
int main()
{
int i, j, temp;
printf("\n\nPattern 1 : \n\n");
/*
9 9 9 9 9
7 7 7 7 7
5 5 5 5 5
3 3 3 3 3
1 1 1 1 1
*/
temp = 9;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", temp);
}
printf("\n");
temp -= 2;
}
// Another method print above pattern
printf("\n\nPattern 1 : \n\n");
for (i = 9; i >= 1; i -= 2)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", i);
}
printf("\n");
}
printf("\n\nPattern 2 : \n\n");
/*
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
*/
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 3 : \n\n");
/*
5 4 3 2 1
5 4 3 2 1
*/
for (i = 1; i <= 2; i++)
{
for (j = 5; j >= 1; j--)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 4 : \n\n");
/*
1 2 3 4
5 6 7 8
9 10 11 12
*/
temp = 1;
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 4; j++)
{
printf("%d ", temp);
temp++;
}
printf("\n");
}
printf("\n\nPattern 5 : \n\n");
/*
1 2 3 4
4 8 12 16
1 2 3 4
4 8 12 16
1 2 3 4
*/
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 4; j++)
{
if (i % 2 == 0)
printf("%d ", j * 4);
else
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 6 : \n\n");
/*
1
2 4
3 5 7
6 8 10 12
9 11 13 15 17
*/
int odd = 1, even = 2;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
printf("%d ", even);
even += 2;
}
else
{
printf("%d ", odd);
odd += 2;
}
}
printf("\n");
}
printf("\n\nPattern 7 : \n\n");
/*
1 2 3 4 5
6 7 8 9
10 11 12
13 14
15
*/
temp = 1;
for (i = 5; i >= 1; i--)
{
for (j = 1; j <= i; j++)
{
printf("%d ", temp);
temp++;
}
printf("\n");
}
return 0;
}
Explanation¶
Explain with AI
Copy the prompt below and paste it into any AI assistant.
You are explaining a C programming code to a beginner.
STRICT RULES:
- Only use the given code. Do NOT assume anything not present.
- Do NOT add extra examples.
- Keep explanation clear and short.
- If something is unclear, say "Not clear from code".
- Follow the exact format below. Do NOT change headings.
FORMAT:
[START]
## What it does
(Explain the overall purpose in 1-2 sentences)
## Step-by-step
(Explain how the code works in steps, simple language)
## Key Concepts
(List concepts like loop, condition, function, etc.)
## Notes
(Mention any limitations, errors, or assumptions)
[END]
CODE (P053.c):
#include <stdio.h>
int main()
{
int i, j, temp;
printf("\n\nPattern 1 : \n\n");
/*
9 9 9 9 9
7 7 7 7 7
5 5 5 5 5
3 3 3 3 3
1 1 1 1 1
*/
temp = 9;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", temp);
}
printf("\n");
temp -= 2;
}
// Another method print above pattern
printf("\n\nPattern 1 : \n\n");
for (i = 9; i >= 1; i -= 2)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", i);
}
printf("\n");
}
printf("\n\nPattern 2 : \n\n");
/*
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
*/
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 5; j++)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 3 : \n\n");
/*
5 4 3 2 1
5 4 3 2 1
*/
for (i = 1; i <= 2; i++)
{
for (j = 5; j >= 1; j--)
{
printf("%d ", j);
}
printf("\n");
}
printf("\n\nPattern 4 : \n\n");
/*
1 2 3 4
5 6 7 8
9 10 11 12
*/
temp = 1;
for (i = 1; i <= 3; i++)
{
for (j = 1; j <= 4; j++)
{
printf("%d ", temp);
temp++;
}
printf("\n");
}
printf("\n\nPattern 5 : \n\n");
/*
1 2 3 4
4 8 12 16
1 2 3 4
4 8 12 16
1 2 3 4
*/
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 4; j++)
{
if (i % 2 == 0)
printf("%d ", j * 4);
else
printf("%d ", j);
}
printf("\n");
}
... (truncated for brevity)