`lucproblem008.c`¶

Problem Statement

Write a problem to print all the prime numbers from 1 to 300.

Metadata¶

Property	Detail
Author	Amit Dutta (amitdutta4255@gmail.com)
License	MIT
Difficulty	Beginner (index: 1 / 10)

Concepts¶

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Sorting (possible)
Iteration

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Source Code¶

#include <stdio.h>
#include <math.h>
#include <stdbool.h>

#define LIMIT 300

int main()
{
    printf("Prime numbers from 1 to 300 :  2"); // as 2 is the only even prime number
    for (int i = 3; i <= LIMIT; i += 2)  // skipping all other even number
    {
        int n = (int)sqrt(i);
        bool prime = true;

        for (int j = 3; j <= n; j += 2)
        // an odd number is only devisable by another odd number.
        // so, skipping even number.
        {
            if (i % j == 0)
            {
                prime = false;
                break;
            }
        }
        if (prime)
        {
            printf("  %d", i);
        }
    }
    return 0;
}

Explanation¶

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (lucproblem008.c):

    #include <stdio.h>
    #include <math.h>
    #include <stdbool.h>

    #define LIMIT 300

    int main()
    {
        printf("Prime numbers from 1 to 300 :  2"); // as 2 is the only even prime number
        for (int i = 3; i <= LIMIT; i += 2)  // skipping all other even number
        {
            int n = (int)sqrt(i);
            bool prime = true;

            for (int j = 3; j <= n; j += 2)
            // an odd number is only devisable by another odd number.
            // so, skipping even number.
            {
                if (i % j == 0)
                {
                    prime = false;
                    break;
                }
            }
            if (prime)
            {
                printf("  %d", i);
            }
        }
        return 0;
    }

lucproblem008.c¶