Skip to content

luc102.c

Problem Statement

What will be the output of the provided program segment involving bitwise operators?

Metadata

Property Detail
Author Amit Dutta amitdutta4255@gmail.com
Date 08 Feb 2026
License MIT License (See the LICENSE file for details)
Difficulty Beginner (index: 1 / 10)

Concepts

Beta Feature

This concept detection system is still in beta and may occasionally show incorrect or incomplete results.

  • Recursion

Actions

Raw View on GitHub

You can print or save this file by opening Raw and using your browser.

Source Code

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i = 32, j = 65, k, l, m, n, o, p;

    k = i | 35; 
    l = ~k; 
    m = i & j;
    n = j ^ 32; 
    o = j << 2; 
    p = i >> 5;

    printf("k = %d l = %d m = %d\n", k, l, m);
    printf("n = %d o = %d p = %d\n", n, o, p);

    return 0;
}

Explanation

Explain with AI

Copy the prompt below and paste it into any AI assistant.

    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (luc102.c):

    #include <stdio.h>
    #include <stdlib.h>

    int main()
    {
        int i = 32, j = 65, k, l, m, n, o, p;

        k = i | 35; 
        l = ~k; 
        m = i & j;
        n = j ^ 32; 
        o = j << 2; 
        p = i >> 5;

        printf("k = %d l = %d m = %d\n", k, l, m);
        printf("n = %d o = %d p = %d\n", n, o, p);

        return 0;
    }