`P031.c`¶

Problem Statement

Find the sum of the series

Metadata¶

Property	Detail
Author	Amit Dutta (amitdutta4255@gmail.com)
License	MIT
Difficulty	Beginner (index: 2 / 10)

Concepts¶

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Pointers
Iteration

Actions¶

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Source Code¶

#include <stdio.h>
#include <math.h>

int main()
{
    double a, res, n;
    int i;

    // s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10)
    {
        res = 0, i = 1;
        printf("--- s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10) ---");
        printf("\nEnter the number : ");
        scanf("%lf", &a);
        while (i <= 10)
        {
            res = res + ((a * a) / i);
            i++;
        }
        printf("S = %g", res);
    }

    // s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n
    {
        res = 0, i = 0;
        printf("\n--- // s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n ---");
        printf("\nEnter the value for a and n : ");
        scanf(" %lf %lf", &a, &n);
        while (i <= n - 1)
        {
            res = res + (pow(i + 1, i + 1) / pow(a, i));
            i++;
        }
        printf("S = %g", res);
    }

    return 0;
}

Explanation¶

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    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (P031.c):

    #include <stdio.h>
    #include <math.h>

    int main()
    {
        double a, res, n;
        int i;

        // s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10)
        {
            res = 0, i = 1;
            printf("--- s = (a ^ 2) + (a ^ 2 / 2) + (a ^ 2 / 3) + ... + (a ^ 2 / 10) ---");
            printf("\nEnter the number : ");
            scanf("%lf", &a);
            while (i <= 10)
            {
                res = res + ((a * a) / i);
                i++;
            }
            printf("S = %g", res);
        }

        // s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n
        {
            res = 0, i = 0;
            printf("\n--- // s = 1 + (2 ^ 2 / a) + (3 ^ 3 / a ^ 2) + ... + n ---");
            printf("\nEnter the value for a and n : ");
            scanf(" %lf %lf", &a, &n);
            while (i <= n - 1)
            {
                res = res + (pow(i + 1, i + 1) / pow(a, i));
                i++;
            }
            printf("S = %g", res);
        }

        return 0;
    }

P031.c¶