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P023.c

Problem Statement

WAP to input the total cost and compute the amount to be paid by the customer.

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 1 / 10)

Concepts

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  • Recursion
  • Pointers

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Source Code

#include <stdio.h>
int main()
{
    double cost, amt;
    printf("Enter the total cost : ");
    scanf("%lf", &cost);
    if (cost <= 2000)
        amt = cost * 0.94;
    else if (cost > 2000 && cost <= 5000)
        amt = cost * 0.9;
    else if (cost > 5000 && cost <= 10000)
        amt = cost * 0.85;
    else if (cost > 10000)
        amt = cost * 0.8;
    printf("\nAmount to be paid : %g", amt);
    return 0;
}

Explanation

Explain with AI

Copy the prompt below and paste it into any AI assistant.

    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (P023.c):

    #include <stdio.h>
    int main()
    {
        double cost, amt;
        printf("Enter the total cost : ");
        scanf("%lf", &cost);
        if (cost <= 2000)
            amt = cost * 0.94;
        else if (cost > 2000 && cost <= 5000)
            amt = cost * 0.9;
        else if (cost > 5000 && cost <= 10000)
            amt = cost * 0.85;
        else if (cost > 10000)
            amt = cost * 0.8;
        printf("\nAmount to be paid : %g", amt);
        return 0;
    }