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APC-PRAC-040.c

Problem Statement

Write a C program to count how many numbers between 100 and 999 have all distinct digits (e.g., 123, 709, 981).

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 1 / 10)

Concepts

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  • Recursion
  • Iteration

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Source Code

#include <stdio.h>

int main()
{
    int i, count = 0, n1, n2, n3;
    printf("Distinct numbers between 100 and 999: ");
    for (i = 100; i <= 999; i++)
    {
        n1 = i / 100;
        n2 = (i % 100) / 10;
        n3 = i % 10;
        if (n1 != n2 && n2 != n3 && n1 != n3)
        {
            printf("%d  ", i);
            count++;
        }
    }
    printf("\nCount: %d\n", count);
    return 0;
}

Explanation

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (APC-PRAC-040.c):

    #include <stdio.h>

    int main()
    {
        int i, count = 0, n1, n2, n3;
        printf("Distinct numbers between 100 and 999: ");
        for (i = 100; i <= 999; i++)
        {
            n1 = i / 100;
            n2 = (i % 100) / 10;
            n3 = i % 10;
            if (n1 != n2 && n2 != n3 && n1 != n3)
            {
                printf("%d  ", i);
                count++;
            }
        }
        printf("\nCount: %d\n", count);
        return 0;
    }