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P067.c

Problem Statement

Write a program using function which concatenates two string s1 and s2 in to a third string

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 2 / 10)

Concepts

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  • Pointers
  • Recursion
  • Array
  • Iteration

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Source Code

#include <stdio.h>

void string_concat(char *s3, char s1[], char s2[])
{
    int l1, l2, i, j, k;
    i = j = k = 0;
    l1 = strlen(s1);
    l2 = strlen(s2);
    s3 = (char *)malloc((l1 + l2 + 1) * sizeof(char));
    while (s1[i] != '\0')
    {
        s3[k++] = s1[i++];
    }
    while (s2[j] != '\0')
    {
        s3[k++] = s2[j++];
    }
    s3[k] = '\0';
    puts(s3);
}

int main()
{
    char s1[] = "JAVA";
    char s2[] = "PYTHON";
    char *s3 = NULL;
    string_concat(s3, s1, s2);
    return 0;
}

Explanation

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    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

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    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

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    [END]

    CODE (P067.c):

    #include <stdio.h>

    void string_concat(char *s3, char s1[], char s2[])
    {
        int l1, l2, i, j, k;
        i = j = k = 0;
        l1 = strlen(s1);
        l2 = strlen(s2);
        s3 = (char *)malloc((l1 + l2 + 1) * sizeof(char));
        while (s1[i] != '\0')
        {
            s3[k++] = s1[i++];
        }
        while (s2[j] != '\0')
        {
            s3[k++] = s2[j++];
        }
        s3[k] = '\0';
        puts(s3);
    }

    int main()
    {
        char s1[] = "JAVA";
        char s2[] = "PYTHON";
        char *s3 = NULL;
        string_concat(s3, s1, s2);
        return 0;
    }