luc076.c¶
Problem Statement
Write a program to count the number of occurrences of any two vowels in succession in a line of text.
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta amitdutta4255@gmail.com |
| Date | 08 Feb 2026 |
| License | MIT License (See the LICENSE file for details) |
| Difficulty | Beginner (index: 2 / 10) |
Concepts¶
Beta Feature
This concept detection system is still in beta and may occasionally show incorrect or incomplete results.
- Recursion
- Array
- Iteration
Actions¶
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Source Code¶
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int is_vowel(char c)
{
c = tolower(c);
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
}
int main()
{
char str[100];
int i, count = 0;
printf("Enter a line of text: ");
gets(str);
printf("Occurrences found:\n");
for (i = 0; str[i] != '\0'; i++)
{
if (is_vowel(str[i]) && is_vowel(str[i+1]))
{
printf("'%c%c' ", str[i], str[i+1]);
count++;
}
}
printf("\n\nTotal number of successive vowels: %d\n", count);
return 0;
}
Explanation¶
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Copy the prompt below and paste it into any AI assistant.
You are explaining a C programming code to a beginner.
STRICT RULES:
- Only use the given code. Do NOT assume anything not present.
- Do NOT add extra examples.
- Keep explanation clear and short.
- If something is unclear, say "Not clear from code".
- Follow the exact format below. Do NOT change headings.
FORMAT:
[START]
## What it does
(Explain the overall purpose in 1-2 sentences)
## Step-by-step
(Explain how the code works in steps, simple language)
## Key Concepts
(List concepts like loop, condition, function, etc.)
## Notes
(Mention any limitations, errors, or assumptions)
[END]
CODE (luc076.c):
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int is_vowel(char c)
{
c = tolower(c);
return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
}
int main()
{
char str[100];
int i, count = 0;
printf("Enter a line of text: ");
gets(str);
printf("Occurrences found:\n");
for (i = 0; str[i] != '\0'; i++)
{
if (is_vowel(str[i]) && is_vowel(str[i+1]))
{
printf("'%c%c' ", str[i], str[i+1]);
count++;
}
}
printf("\n\nTotal number of successive vowels: %d\n", count);
return 0;
}