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APC-PRAC-037.c

Problem Statement

Show all the armstrong number between a range.

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Author Amit Dutta amitdutta4255@gmail.com
Date 12 Dec 2025
License MIT License (See the LICENSE file for details)
Difficulty Beginner (index: 1 / 10)

Concepts

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  • Recursion
  • Iteration

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Source Code

#include <stdio.h>
#include <math.h>

#define lowerBound 100
#define upperBound 999

int isArmstrongNumber(int);

int isArmstrongNumber(int n)
{
    int temp = n, sum = 0, count = 0;
    while (temp > 0)
    {
        count++;
        temp /= 10;
    }
    temp = n;
    while (temp > 0)
    {
        sum += (int)pow(temp % 10, count);
        temp /= 10;
    }
    return sum == n;
}

int main()
{
    int n, i, count = 0;
    printf("Armstrong number between %d and %d are:  ", lowerBound, upperBound);
    for (i = lowerBound; i <= upperBound; i++)
        if (isArmstrongNumber(i))
        {
            printf("%d  ", i);
            count++;
        }
    printf("\n\nCount: %d\n", count);
    return 0;
}

Explanation

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    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

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    ## Key Concepts

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    [END]

    CODE (APC-PRAC-037.c):

    #include <stdio.h>
    #include <math.h>

    #define lowerBound 100
    #define upperBound 999

    int isArmstrongNumber(int);

    int isArmstrongNumber(int n)
    {
        int temp = n, sum = 0, count = 0;
        while (temp > 0)
        {
            count++;
            temp /= 10;
        }
        temp = n;
        while (temp > 0)
        {
            sum += (int)pow(temp % 10, count);
            temp /= 10;
        }
        return sum == n;
    }

    int main()
    {
        int n, i, count = 0;
        printf("Armstrong number between %d and %d are:  ", lowerBound, upperBound);
        for (i = lowerBound; i <= upperBound; i++)
            if (isArmstrongNumber(i))
            {
                printf("%d  ", i);
                count++;
            }
        printf("\n\nCount: %d\n", count);
        return 0;
    }