`P019.c`¶

Problem Statement

WAP to input the distance covered and calculate the amount to be paid by the passanger. Distance Rate =<5KM RS 90 next 10KM RS 20/KM next 10KM RS 10/KM more than 25KM RS 9/KM

Metadata¶

Property	Detail
Author	Amit Dutta (amitdutta4255@gmail.com)
License	MIT
Difficulty	Beginner (index: 1 / 10)

Concepts¶

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Recursion

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Source Code¶

#include <stdio.h>
int main()
{
    double dis, amt;
    printf("Enter the distance : ");
    scanf("%lf", &dis);
    if (dis <= 5.0)
        amt = 90.0;
    else if (dis > 5.0 && dis <= 15.0)
        amt = 90.0 + (dis - 5.0) * 20;
    else if (dis > 15.0 && dis <= 25.0)
        amt = 90.0 + 200.0 + (dis - 15.0) * 10;
    else if (dis > 25.0)
        amt = 90.0 + 200.0 + 100.0 + (dis - 25.0) * 9;
    printf("\nAmount to be paid : %g", amt);
    return 0;
}

Explanation¶

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Copy the prompt below and paste it into any AI assistant.

    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (P019.c):

    #include <stdio.h>
    int main()
    {
        double dis, amt;
        printf("Enter the distance : ");
        scanf("%lf", &dis);
        if (dis <= 5.0)
            amt = 90.0;
        else if (dis > 5.0 && dis <= 15.0)
            amt = 90.0 + (dis - 5.0) * 20;
        else if (dis > 15.0 && dis <= 25.0)
            amt = 90.0 + 200.0 + (dis - 15.0) * 10;
        else if (dis > 25.0)
            amt = 90.0 + 200.0 + 100.0 + (dis - 25.0) * 9;
        printf("\nAmount to be paid : %g", amt);
        return 0;
    }

P019.c¶