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P034.c

Problem Statement

Get sum of even position digit and odd position digit

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 1 / 10)

Concepts

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  • Recursion
  • Iteration

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Source Code

#include <stdio.h>
int main()
{
    int inp, temp, index = 1, even = 0, odd = 0;
    printf("Enter the numebr : ");
    scanf("%d", &inp);
    temp = inp;
    while (temp > 0)
    {
        if (index % 2 == 0)
            even += temp % 10;
        else
            odd += temp % 10;
        temp /= 10;
        index++;
    }
    printf("\nSum of even position digits : %d"
           "\nSum of odd position digits : %d",
           even, odd);
    return 0;
}

Explanation

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (P034.c):

    #include <stdio.h>
    int main()
    {
        int inp, temp, index = 1, even = 0, odd = 0;
        printf("Enter the numebr : ");
        scanf("%d", &inp);
        temp = inp;
        while (temp > 0)
        {
            if (index % 2 == 0)
                even += temp % 10;
            else
                odd += temp % 10;
            temp /= 10;
            index++;
        }
        printf("\nSum of even position digits : %d"
               "\nSum of odd position digits : %d",
               even, odd);
        return 0;
    }