luc032.c¶
Problem Statement
Write a program to recieve an integer and find its octal equivalent. (Hint : To obtain octal equivalent of an integer, Divide it continuously by 8 till dividend does not become zero, then write the remainders obtained in reverse derection.)
Metadata¶
| Property | Detail |
|---|---|
| Author | Amit Dutta (amitdutta4255@gmail.com) |
| License | MIT |
| Difficulty | Beginner (index: 1 / 10) |
Concepts¶
Beta Feature
This concept detection system is still in beta and may occasionally show incorrect or incomplete results.
- Recursion
- Array
- Iteration
Actions¶
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Source Code¶
#include <stdio.h>
int main()
{
int octal[20], decimal, index = 0, temp, rem;
printf("Enter the decimal number : ");
scanf("%d", &decimal);
temp = decimal;
while (temp != 0)
{
rem = temp % 8;
temp = temp / 8;
octal[index] = rem;
index++;
}
printf("\nDeciaml %d to octal : ", decimal);
while ((index - 1) >= 0)
{
printf("%d", octal[index - 1]);
index--;
}
return 0;
}
Explanation¶
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FORMAT:
[START]
## What it does
(Explain the overall purpose in 1-2 sentences)
## Step-by-step
(Explain how the code works in steps, simple language)
## Key Concepts
(List concepts like loop, condition, function, etc.)
## Notes
(Mention any limitations, errors, or assumptions)
[END]
CODE (luc032.c):
#include <stdio.h>
int main()
{
int octal[20], decimal, index = 0, temp, rem;
printf("Enter the decimal number : ");
scanf("%d", &decimal);
temp = decimal;
while (temp != 0)
{
rem = temp % 8;
temp = temp / 8;
octal[index] = rem;
index++;
}
printf("\nDeciaml %d to octal : ", decimal);
while ((index - 1) >= 0)
{
printf("%d", octal[index - 1]);
index--;
}
return 0;
}