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APC-PRAC-014.c

Problem Statement

Write a program to calculate and display the maturity amount taking the sum and number of days as input. No. of Days Rate of Interest =========== ================ <= 180 5.57 % 181 - 364 7.75 % 365 - 500 9.25 % > 500 9.15 %

Metadata

Property Detail
Author Amit Dutta (amitdutta4255@gmail.com)
License MIT
Difficulty Beginner (index: 1 / 10)

Concepts

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  • Recursion
  • Pointers

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Source Code

#include <stdio.h>

int main()
{
    double p, t, r, si;
    int days;
    printf("Enter the Principle, Time (Days) : ");
    scanf("%lf %d", &p, &days);
    if (days > 0 && days <= 180)
        r = 5.57;
    else if (days > 180 && days <= 364)
        r = 7.75;
    else if (days > 364 && days <= 500)
        r = 9.25;
    else if (days > 500)
        r = 9.15;
    si = (p * t * r) / 100;
    printf("\nMaturity Amount : %d", si + p);
    return 0;
}

Explanation

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    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (APC-PRAC-014.c):

    #include <stdio.h>

    int main()
    {
        double p, t, r, si;
        int days;
        printf("Enter the Principle, Time (Days) : ");
        scanf("%lf %d", &p, &days);
        if (days > 0 && days <= 180)
            r = 5.57;
        else if (days > 180 && days <= 364)
            r = 7.75;
        else if (days > 364 && days <= 500)
            r = 9.25;
        else if (days > 500)
            r = 9.15;
        si = (p * t * r) / 100;
        printf("\nMaturity Amount : %d", si + p);
        return 0;
    }