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APC-PRAC-023.c

Problem Statement

Pattern : (a) 1, -3, 5, -7, 9, -11, ... upto n times (b) 0, 3, 8, 15, ... upto n times

Metadata

Property Detail
Author Amit Dutta amitdutta4255@gmail.com
Date 12 Dec 2025
License MIT License (See the LICENSE file for details)
Difficulty Beginner (index: 2 / 10)

Concepts

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  • Pointers
  • Sorting (possible)
  • Iteration

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Source Code

#include <stdio.h>
#include <stdbool.h>

int main()
{
    int n, i, temp = 1;
    bool isNegative = true;
    printf("Enter the n : ");
    scanf("%d", &n);
    printf("\nPattern A :");
    for (i = 1; i <= n; i++)
    {
        if (!isNegative)
        {
            printf("  %d", temp * -1);
            isNegative = true;
        }
        else
        {
            printf("  %d", temp);
            isNegative = false;
        }
        temp += 2;
    }
    printf("\nPattern B :");
    for (i = 1; i <= n; i++)
    {
        temp = (i * i) - 1;
        printf("  %d", temp);
    }
    return 0;
}

Explanation

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Copy the prompt below and paste it into any AI assistant.

    You are explaining a C programming code to a beginner.

    STRICT RULES:

    - Only use the given code. Do NOT assume anything not present.

    - Do NOT add extra examples.

    - Keep explanation clear and short.

    - If something is unclear, say "Not clear from code".

    - Follow the exact format below. Do NOT change headings.

    FORMAT:

    [START]

    ## What it does

    (Explain the overall purpose in 1-2 sentences)

    ## Step-by-step

    (Explain how the code works in steps, simple language)

    ## Key Concepts

    (List concepts like loop, condition, function, etc.)

    ## Notes

    (Mention any limitations, errors, or assumptions)

    [END]

    CODE (APC-PRAC-023.c):

    #include <stdio.h>
    #include <stdbool.h>

    int main()
    {
        int n, i, temp = 1;
        bool isNegative = true;
        printf("Enter the n : ");
        scanf("%d", &n);
        printf("\nPattern A :");
        for (i = 1; i <= n; i++)
        {
            if (!isNegative)
            {
                printf("  %d", temp * -1);
                isNegative = true;
            }
            else
            {
                printf("  %d", temp);
                isNegative = false;
            }
            temp += 2;
        }
        printf("\nPattern B :");
        for (i = 1; i <= n; i++)
        {
            temp = (i * i) - 1;
            printf("  %d", temp);
        }
        return 0;
    }